8-bit PIC (請註明使用元件編號):: PIC24FJ64GA006關於ADC轉態的問題
引用:
請問，24FJ64GB002 規格書內
REGISTER 22-4: AD1CHS: A/D INPUT SELECT REGISTER
bit 7 CH0NA: Channel 0 Negative Input Select for MUX A Multiplexer Setting bit
1 = Channel 0 negative input is AN1
0 = Channel 0 negative input is VR-
bit 4-0 CH0SA<4:0>: Channel 0 Positive Input Select for MUX A Multiplexer Setting bits
Implemented combinations are identical to those for CH0SB<4:0> (above)
01011 = Channel 0 positive input is AN11
如果我將CH0NA 設1; CH0SA<4:0>設01011,
那是否代表，ADC的數值=AN11-AN1的ADC轉換值? (已知:AN11>=AN1)
(自己try-error也是可以啦，但我先確認是否誤解規格書的說明)
謝謝回覆。
引用:
Ryang 寫道：
...
ADCHS = 0x0006 ; // CH0正端輸入選擇AN6，負端輸入為Vss
IEC0bits.ADIE = 1 ; // 打開AD的中斷
IPC2bits.ADIP = 7 ; // 中斷等級＝7 ( 最高優先權中斷等級 )
ADCON1bits.ADON = 1; // 啟動 AD
}
[/code]
請問，24FJ64GB002 規格書內
REGISTER 22-4: AD1CHS: A/D INPUT SELECT REGISTER
bit 7 CH0NA: Channel 0 Negative Input Select for MUX A Multiplexer Setting bit
1 = Channel 0 negative input is AN1
0 = Channel 0 negative input is VR-
bit 4-0 CH0SA<4:0>: Channel 0 Positive Input Select for MUX A Multiplexer Setting bits
Implemented combinations are identical to those for CH0SB<4:0> (above)
01011 = Channel 0 positive input is AN11
如果我將CH0NA 設1; CH0SA<4:0>設01011,
那是否代表，ADC的數值=AN11-AN1的ADC轉換值? (已知:AN11>=AN1)
(自己try-error也是可以啦，但我先確認是否誤解規格書的說明)
謝謝回覆。
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